I created another theorem . If u wanna ask something leave a comment.
If x is a number with N digits where N>1 then the sum of ' the difference between x and its mirror reverse' and its mirror reverse will be a multiple of 9.
Ex.647
746 - 647 = 99 or 099
99 + 99 = 198
or 99 + 990 = 1089
ADIEU !!!!!
FOWL
Wednesday, 20 June 2007
Another theorem
Subscribe to:
Post Comments (Atom)
Counter
5 comments:
its not valid for 10
10-1=9 +1=10,not a multiple of 9...
.......
...
.
ok nw i got wat u were trying 2 say...
ok fine....good
This isn't really a new discovery.
Take a three digit number with digits xyz. The no. can be written as 100x+10y+z.
On reversing the digits we get: 100z+10y+x.
On subtracting:
(100x+10y+z)-(100z+10y+x)=99x-99z
=99(x-z)
Hence, all such numbers will be a multiple of 99.
Hey man probably u didnt realise.
i had just entered ninth standard at the time of creating this blog. so there.
yes i know that thanks to elaborate... the posts are in chronological order with me growing up.
Your blog keeps getting better and better! Your older articles are not as good as newer ones you have a lot more creativity and originality now keep it up!
Post a Comment